Amit Singh
- Rate UGX 32,638
- Response 1h
UGX 32,638/hr
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- Maths
- Algebra
- Trigonometry
- Arithmetic
- Statistics
I am doing my graduation right now. I have done my 12th with 85% marks from ISC Boards. I have scored 90+ marks in maths.
- Maths
- Algebra
- Trigonometry
- Arithmetic
- Statistics
Lesson location
About Amit Singh
Hello, My name is Amit Singh Yadav.
I am B.Sc student of Davv , Indore.
I have done my 12th in 2020 (but before the pandemic) with a 85% marks. I am good in mathematics and reasoning. As I also have basic knowledge regarding physical education.
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About the lesson
- Primary
- Secondary
- Tertiary
- +8
levels :
Primary
Secondary
Tertiary
University
Adult Education
Masters
Diploma
PhD (Doctor of Philosophy)
Post-Graduate Diploma in Legal Practice
MBA
Early childhood education
- English
All languages in which the lesson is available :
English
I know to explain the subject to the student , as i am also a student and face the same issue which the today student face.
Here, I am solving a question based on average
The given numbers are 71,72,55,67,85
so now we have to calculate the average of these numbers?
solution -
As teacher taught in school “sum of all the number/number of observations “
Let’s Come to knew way -
Assume any number nearest to given number like i am assuming “70” for given question .
Now , check how each number is large or more than the number which we assume
So, +1,+2,-15,-3,+5.
Now the sum the number =-10 .
Now number we get is “10” , Divide number obtain after sum divided by number of number digit present.
So,-10/5 =-2.
Now, add “70 “and “-2”
So we get the average of numbers is 68.
By this we can solve any type of trick or complex question on average.
I know many more tricks regarding many topics.
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Rates
Rate
- UGX 32,638
Pack prices
- 5h: UGX 160
- 10h: UGX 320
online
- UGX 32,638/hr
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